5/x^2-x-2-2/x^2-4=4/x^2+3x+2

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Solution for 5/x^2-x-2-2/x^2-4=4/x^2+3x+2 equation:



5/x^2-x-2-2/x^2-4=4/x^2+3x+2
We move all terms to the left:
5/x^2-x-2-2/x^2-4-(4/x^2+3x+2)=0
Domain of the equation: x^2!=0
x^2!=0/
x^2!=√0
x!=0
x∈R
Domain of the equation: x^2+3x+2)!=0
x∈R
We add all the numbers together, and all the variables
-1x+5/x^2-2/x^2-(4/x^2+3x+2)-6=0
We get rid of parentheses
-1x+5/x^2-2/x^2-4/x^2-3x-2-6=0
We multiply all the terms by the denominator
-1x*x^2-3x*x^2-2*x^2-6*x^2+5-2-4=0
We add all the numbers together, and all the variables
-8x^2-1x*x^2-3x*x^2-1=0
Wy multiply elements
-8x^2-1x^3-3x^3-1=0
We do not support expression: x^3

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